If two times the larger of the two numbers is divided
by the smaller one, we get 3 as quotient and 5 as the
remainder. Also, if ten times the smaller number is
divided by the larger one, we get 4 as quotient and
2 as remainder. Find the numbers.
Answers
Let x and y be the two numbers. such that x > y
Now,
According to the Question
- Case 1
Two times the larger number divided by the smaller one we get 3 as Quotient and 5 as Remainder.
This can be represented in the form of linear equation as:
- Case 2
Ten times the smaller number divided by the larger one, we get 4 as Quotient and 2 as Remainder.
This can be represented in the form of linear equation as:
Now,
Subtract (2) from (1)
We get y = 3, Put value of y in (1)
-- 2x - 3(3) = 5
-- 2x - 9 = 5
-- 2x = 14
-- x = 7
We get x = 7
Therefore, Numbers are 7 and 3.
AnswEr :
let first no.(larger) be n and second no.(smaller) be m.
Dividend = Divisor × Quotient + Remainder
⋆ If two times the larger of the two numbers is divided by the smaller one, we get 3 as quotient and 5 as the remainder.
⇒ 2 times Larger No. = Smaller No. × 3 + 5
⇒ 2 × n = m × 3 + 5
⇒ 2n = 3m + 5
⇒ 2n - 3m = 5⠀ ⠀⠀⠀⠀— eq.( I )
⋆ If ten times the smaller number is divided by the larger one, we get 4 as quotient and 2 as remainder.
⇒ 10 times Smaller No. = Larger No. × 4 + 2
⇒ 10 × m = n × 4 + 2
⇒ 10m = 4n + 2
⇒ 10m = 2(2n + 1)
- Dividing Both term by 2
⇒ 5m = 2n + 1
⇒ 2n - 5m = - 1⠀ ⠀⠀⠀— eq.( II )
_________________________________
• Subtracting eq.( I ) from eq.( II ) :
⇝ 2n - 5m = - 1
⇝ 2n - 3m = 5⠀⠀
⠀⠀-⠀⠀+⠀⠀⠀-
_________________
⇝ - 5m + 3m = - 1 - 5
⇝ - 2m = - 6
- Dividing Both term by - 2
⇝ m = 3
• Putting the value of m in ( I ) :
⇝ 2n - 3m = 5
⇝ 2n - 3 × 3 = 5
⇝ 2n - 9 = 5
⇝ 2n = 5 + 9
⇝ 2n = 14
- Dividing Both term by 2
⇝ n = 7
∴ So, Larger No. is 7 and Smaller No. is 3.