if two vector 2i+3j–k and –4i–6j–xk are parallel to each other the value of i be
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Since the vectors are parallel, their cross product is zero.
⇒(2i^+3j^−k^)×(4i^+6j^+xk^)=0.
⇒i^(3x+6)−j^(2x+4)+k^(12−12)=0.
⇒3x+6=0 and 2x+4=0.
⇒x=−2.
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