If two ventices of an equilateral triangle are (3,0) and (6,0) find the third vertex.
Answers
Answered by
1
Dear student,
The given vertices are A(3, 0) and B(6, 0).
Let the coordinates of the third vertex be C(x, y).
We have AB = BC = CA
AB2 = BC2 = CA2
Using distance formula, we have:
(6-3)2 + (0-0)2 = (x-6)2 + (y-0)2 = (x-3)2 + (y-0)2
9 = x2 + 36 - 12x + y2 = x2 + 9 - 6x + y2
Now, consider x2 + 36 - 12x + y2 = x2 + 9 - 6x + y2 and find the value of x from this relation.
Then, consider the relation 9 = x2 + 36 - 12x + y2 to get the value of y and thus obtain the third vertex of the equilateral triangle.
The given vertices are A(3, 0) and B(6, 0).
Let the coordinates of the third vertex be C(x, y).
We have AB = BC = CA
AB2 = BC2 = CA2
Using distance formula, we have:
(6-3)2 + (0-0)2 = (x-6)2 + (y-0)2 = (x-3)2 + (y-0)2
9 = x2 + 36 - 12x + y2 = x2 + 9 - 6x + y2
Now, consider x2 + 36 - 12x + y2 = x2 + 9 - 6x + y2 and find the value of x from this relation.
Then, consider the relation 9 = x2 + 36 - 12x + y2 to get the value of y and thus obtain the third vertex of the equilateral triangle.
Similar questions