If two vertices of a parallelogram are (3,2),(-1,0) and the diagonals cut at (2,-5). Find the other vertices of the parallelogram
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Answer:
C(5,-10) & D(1,-12)
Step-by-step explanation:
Let A(3,2), B(-1,0) & E(2,-5)
The diagonals of a parallelogram bisect each other
So,
Using mid-point formula
(for line BC)
E(2,-5) = [-1+x/2,0+y/2]
2=-1+x/2 & -5=y/2
4=-1+x & -10=y
x=5 & y=-10
Therefore, coordinate C is C(5,-10).
(for line AD)
E(2,-5) = [3+x/2,2+y/2]
2=3+x/2 & -5=2+y/2
4=3+x & -10=2+y
x=1, y=-12
Therefore, coordinate D is D(1,-12).
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