Question

If two vertices of a square are (3,2) and (-1,-2) , find the coordinate of the other two vertices ?

plz someone ans .

Answer 1

Given,

A( x1, y1) = (3,2)
B(x2, y2) = (-1,-2)

$P(xy) = \sqrt{ {( x_{2} - x_{1})}^{2} + {( y_{2} - y_{1})}^{2} } \\ \\ = \sqrt{ {(1 - 3)}^{2} + {( - 2 - 2)}^{2} } \\ \\ = \sqrt{ {( - 4)}^{2} + {( - 4)}^{2} } \\ \\ = \sqrt{16 + 16} \\ \\ = \sqrt{32} \\ \\ = 4 \sqrt{2} \: units$

$\huge \bold{answer \: = {4 \sqrt{2} } }$