Question

If two vertices of an equilateral triangle are (0, 0) and (3, 0), find the third vertex.​

Answer 1

$\displaystyle\large\underline{\sf\red{Given}}$

✭ Two vertex of an equilateral triangle are (0,0) & (3,0)

$\displaystyle\large\underline{\sf\blue{To \ Find}}$

◈ The third vertex?

$\displaystyle\large\underline{\sf\gray{Solution}}$

Answer has also been attached!!

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$\underline{\bigstar\:\textsf{According to the given Question :}}$

Remaining Answer

➳ $\displaystyle\sf (\dfrac{3}{2})^2-6(\dfrac{3}{2})+b^2 = 0$

➳ $\displaystyle\sf \dfrac{9}{4} - 9+b^2 = 0$

Multiplying the whole Equation by 4,

➳ $\displaystyle\sf 4\bigg\lgroup \dfrac{9}{4} - 9+b^2 = 0 \bigg\rgroup$

➳ $\displaystyle\sf 9-36+4b^2 = 0$

➳ $\displaystyle\sf -27+4b^2 = 0$

➳ $\displaystyle\sf 4b^2 = 27$

➳ $\displaystyle\sf b^2 = \dfrac{27}{4}$

➳ $\displaystyle\sf b = \sqrt{\dfrac{27}{4}}$

➳ $\displaystyle\sf \pink{b = \dfrac{\sqrt{27}}{4}}$

$\displaystyle\sf \therefore a = \dfrac{3}{2} \ \& \ b = \dfrac{\sqrt{27}}{4}$

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Answer 2

Answer:

3/2 and 3 root 3/2

Step-by-step explanation:

pls solve