Question

If two vertices of an equilateral triangle are (0 0) and (3 root 3) find the area of the triangle

Answer 1

Step-by-step explanation:

$a = \sqrt{ {(3 - 0)}^{2} + {( \sqrt{3} - 0) }^{2} } \\ = \sqrt{9 + 3} \\ = \sqrt{12} \\ area = \frac{ \sqrt{3} }{4} {a}^{2} \\ = \frac{ \sqrt{3} }{4} {( \sqrt{12}) }^{2} \\ = \frac{ \sqrt{3} }{4} \times 12 \\ = 3 \sqrt{3} \: sq \:.units \\ = = = = = = = = = = = = = = =$