Question

if two vertices of an equilateral triangle are (-2,0) and (4,0). find the third vertex. find its area.

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Now,AC=BC

⇒(x+4)2+(y−0)2

​=(x−4)2+(y−0)2

​

⇒(x+4)2+y2=(x−4)2+y2

⇒16x=0

⇒x=0

Again

,AC=BC=AB

⇒AC=AB

⇒(x+4)2+(y−0)2

​=(4+4)2+02

​

⇒(x+4)2+y2=64

⇒(0+4)2+y2=64

⇒y2=48

⇒y=±43

​

Hence, the coordinates of the third vertex are C(0,43

​)andD(0,−43

​).