Question

if two vertices of an isosceles right triangle are A(-1,-7) and B(-7,-1), then find coordinates of third vertex of the triangle ABC (given= angle C= 90°)​ plzz answers only

Answer 1

Step-by-step explanation:

1. Given that ABC is an isosceles triangle.
2. The two vertices are B (1,3) = (x₂,y₂) and C (-2,7) = (x₂,y₂)
3. We have to find the co-ordinates of the vertex A
4. Since the triangle is an isosceles triangle So,
5. AB = AC ............. (1)
6. And also vertex A lies on y-axis.
7. Let A be (0,y) = (x₁,y₁)
8. Equation (1) ⇒ AB = AC
9. √ [(x₂ - x₁)² + (y₂ - y₁)²] = √ [(x₂ - x₁)² + (y₂ - y₁)²]
10. (1 - 0)² + (3 - y)² = (- 2 - 0)² + (7 - y)²
11. 1 + (3 - y)² = 2 + (7 - y)²
12. 1 + 9 + y² - 6y = 2 + 49 + y² -14y
13. 10 - 6y = 51 - 14y
14. 14y - 6y = 51 - 10
15. 9y = 41
16. y=
17. 9
18. 41
21. y = 4.6
22. So, co-ordinates of the vertex A are A (0,4.6)

Answer 2

Step-by-step explanation:

$\bf\ Hey \ mate \ plz \ mark \ me \ as \ the \ brainliest$