Question

If two waves, each of intensity 0 i , having the same frequency but differing by a constant phase angle of 60 , superpose at a certain point in space, then the intensity of resultant wave is

Answer 1

Answer:

If two waves each of intensity I having the same frequency but differing by a constant phase angle of 60 ,superimposing at a certain point in space then the intensity of the resultant wave is.

Answer 2

Given that,

Phase angle = 60°

If two waves, each of intensity $I_{0}$ having the same frequency.

We need to calculate the intensity of resultant wave

Using  formula of intensity

$I=I_{1}+I_{2}+2\sqrt{I_{1}I_{2}}\cos\theta$

Here, $I=I_{1}=I_{2}$

Where, I = intensity of wave

Put the value into the formula

$I=2I+2\sqrt{I^2}\cos60$

$I=2I+2I\times\dfrac{1}{2}$

$I=3I$

Hence, the intensity of resultant wave is 3I