if two zero of the polynomial are 4x2 - 2x + (k-4) are reciprocal to each other find the value of k
Answers
Answered by
53
let two zeroes be a and 1/a
product of zeroes = (k-4)/4
a × 1/a = ( k-4)/4
k - 4 = 4
k = 8
✌✌Dhruv✌✌✌
product of zeroes = (k-4)/4
a × 1/a = ( k-4)/4
k - 4 = 4
k = 8
✌✌Dhruv✌✌✌
Answered by
60
Answer:
k = 8
Step-by-step explanation:
Let one zero be α.Then, the other zero is its reciprocal = 1/α.
Given Quadratic Equation is 4x² - 2x + (k - 4)
Here, a = 4, b = -2, c = (k - 4).
Product of roots:
We know that Product of roots = c/a.
⇒ α * 1/α = (k - 4)/4
⇒ 1 = (k - 4)/4
⇒ 4 = k - 4
⇒ k = 8.
Therefore, the value of k = 8.
Hope it helps!
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