If two zeroes of polynomial p(x)= x4 – 6x3 – 26x2 + 138x – 35 are 2± √3, find other zeroes.
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Dividing p(x) by x2 - 4x + 1
Hence, other two zeroes of p(x) are -5 and 7.
Hence, other two zeroes of p(x) are -5 and 7.
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