If two zeroes of the polynomial 2(x^4)+(x^3)-14(x^2)-19x-6 are -2 and -1 , then the other zeroes are
1 point
3 and 1/2
-3 and -1/2
-3 and 1/2
3 and -1/2
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Answer:
So you have two roots for a biquadratic equation and required to find the other two. As only the formula to find roots of a quadratic equation is given to you. You first have to convert the biquadratic polynomial to a quadratic polynomial.
For doing that,
Step-1
Form a quadratic equation by using the roots given(α + β = - ba and αβ = ca use these two conditions to find a, b and c. Then fill the values of found a,b, and c in x2 + bax + ca = 0 (Since, a ≠ 0))
Step-2
Now divide the biquadratic polynomial with the quadratic polynomial you have just formed. (use long division method)
Step-3
Now you will get a quadratic equation as your quotient form the long division. The roots of that quotient will be the required roots.
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