Question

If two zeroes of the polynomial f(x) = x3 - 4x2 - 3x + 12 are v3 and - V3, then
find its third zero.

Answer 1

Answer:

4

Step-by-step explanation:

$p(x) = {x}^{3} - 4 {x}^{2} - 3x + 12 \\ \alpha + \beta + \gamma = \frac{ - b}{a} \\ \sqrt{3} - \sqrt{3} + \gamma = \frac{4}{1} \\ \gamma = 4$

Third zero=4