Question

IF TWO ZEROES OF THE POLYNOMIAL
${x}^{4} - 6 {x}^{3} - 26 {x}^{2} - 138x - 35$
ARE
$2 - + \sqrt{3}$
, FIND OTHER ZEROES..

DON'T SPAM PLEASE..✌️​

Answer 1

Step-by-step explanation:

(x−2+√3)(x−2− √3)=x²+4−4x−3

= x²−4x+1 is a factor of the given polynomial.

Using division algorithm, we get

x⁴−6x³−26x²+138x−35=(x²−4x+1)(x²−2x−35)

So, (x²−2x−35) is also a factor of the given polynomial.

x²−2x−35=x²−7x+5x−35

=x(x−7)+5(x−7)

=(x−7)(x+5)

Hope it helps ❤️