if two zeroes of the polynomial x^3-3x^2+2 are 1+√3 and 1-√3 find the third zero
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Answer:
-5
Step-by-step explanation:
Formula: x^3 + 3x^2 + 0x + 2
Sum of roots = -b/a = -3/1 = -3
1st root = 1 + √3
2nd root = 1 - √3
1st root + 2nd root + 3rd root = -3
3rd root = -3 - (1st root + 2nd root)
= -3 - (2)
= -5
Brainliest please
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