if two zeroes of the polynomial x4-6x3-26x2+138x-35 are 2± √3
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Two zeroes are x=2+3^1/2 and x=2-3^1/2
So, x-2-3^1/2=0 and x-2+3^1/2 =0 equate both of them you get,
(x-2)^2-(3^1/2)^2,
This gives us,
X^2-4x+1=0,
Subtract it from the polynomial you will get an quadratic equation and solve it you will get the answers
So, x-2-3^1/2=0 and x-2+3^1/2 =0 equate both of them you get,
(x-2)^2-(3^1/2)^2,
This gives us,
X^2-4x+1=0,
Subtract it from the polynomial you will get an quadratic equation and solve it you will get the answers
VishalSwabhimani:
plz sir solve fully
the quotient of the polynomial after dividing will be x^2- 2x - 35 = 0,after solving you will get zeroes 7 and - 5
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