Question

if two zeroes of the polynomials are 8 and 6 find the polynomials
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Answer 1

Answer:

Here Given two zero

$\alpha = 8 \\ \beta = 6$

NOW

$x ^{2} + ( \alpha + \beta )x + \alpha \beta = 0 \\ x^{2} + (8 + 6) + (8 \times 6) =0\\x^{2} + 14x + 48 = 0$