If two zeroes of x+(a+1)x+b are 2,-3 then find value of a and b
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ANSWER:
- Value of a is 0 and b is (-6)
GIVEN:
- Two zeroes of x+(a+1)x+b are 2,-3.
TO FIND:
- Value of 'a'and 'b'.
SOLUTION:
=> P(x) = x+(a+1)x+b
Sum of zeros:
= 2+(-3)
= -1
Product of zeros:
= 2(-3)
= -6
Formula:
=> Sum of zeroes (α+β) = -(Coefficient of x)/Coefficient of x²
Putting the values:
=> -1 = -(a+1)/1
=> 1 = a+1
=> a = 1-1
=> a = 0
Formula:
=> Product of zeroes (αβ) = Constant term/ Coefficient of x²
Putting the values:
=> -6 = b/1
=> b = (-6).
Value of a is 0 and b is (-6)
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