Question

If two zeros of polynomial x square - 85x+c=0 are prime numbers what is the value of the digit of c

Answer 1

Answer:

162

Step-by-step explanation:

Consider the equation  

       So x^2 – 85 x + c  = 0

Given roots of the equation are prime numbers.

Let α and β are the roots of the equation.

So sum of roots = - b / a

                         = - (-85) / 1

                           = 85

α + β = 85

Sum of two prime numbers is always even but not when the prime number is 2.

So 85 is an odd number. Now α = 2

β= 85 – 2 = 81

c = αβ

  = 2 x 81

    =   162.