if two zeros of the polynomial 2x^4 + 5x^3 - 13x^2 - 25x + 15 are √5 and -√5 find the other zeros of the polynomial
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sum of zeroes = -5/2
√5 -√5 + a + b= -5/2
a+ b= -5/2
Product = 15/2
√5(-√5)(a)(b)= 15/2
ab= -15/10 = -3/2
a+ b= -5/2
a= -5/2 - b
ab= -3/2
-5/2 - b)(b)= -3/2
5/2 b + b^2 = 3/2
5b + 2 b^2 = 3
2b^2 + 5b -3=0
2b^2 +6b - b -3= 0
2b( b+3) -( b+3)= 0
(2b -1)( b+3)=0
b= 1/2, -3
ab= -3/2
a= -3/2b
= -3/ 2× 1/2 = -3
a= -3/ 2(-3)
= 1/2
So 2 zeroes are 1/2, -3
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