Question

if two zeros of the polynomial p of x is equal to x cube + 2 x square - 9 x minus 18 3 and minus 3 find other zeros of polynomial p of x​

Answer 1

$Given \:p(x) = x^{3} + 2x^{2}-3x-18$

$3 \:and \:-3 \:are \: zeroes \:of \:p(x)$

$(x-3)\:and \:(x+3) \:are \: factors \:p(x).$

$(x-3)(x+3) = x^{2} - 3^{2} = x^{2} - 9 \:is \:also \\factor \:of \:p(x)$

x²-9) x³+2x²-9x-18(x+2

******x³ + 0 - 9x

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********* 2x² + 0 - 18

********* 2x² + 0 - 18

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Remainder (0)

Therefore.,

$\red { Factors \:p(x) }\green {= (x-3)(x+3)(x+2)}$

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Answer 2

Answer:

minus 1 is equal to 1 Cube + 1 x square - 9 (mein 1 - 9 is equal to minus 1 is equal to 1 + 1 - 9 - 9 is equal to 2