If two zeros of the polynomial x*- 6x3 - 26x + 138x - 35 are 2 + 13, find other zeroes
Answers
The two zeroes of the polynomial is 2+
3
,2−
3
Therefore, (x−2+
3
)(x−2−
3
)=x
2
+4−4x−3
= x
2
−4x+1 is a factor of the given polynomial.
Using division algorithm, we get
x
4
−6x
3
−26x
2
+138x−35=(x
2
−4x+1)(x
2
−2x−35)
So, (x
2
−2x−35) is also a factor of the given polynomial.
x
2
−2x−35=x
2
−7x+5x−35
=x(x−7)+5(x−7)
=(x−7)(x+5)
Hence, 7 and −5are the other zeros of this polynomial
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9th>Maths>Polynomials>Remainder Theorem>If two zeroes of
The two zeroes of the polynomial is 2+3,2−3
Therefore, (x−2+3)(x−2−3)=x2+4−4x−3
= x2−4x+1 is a factor of the given polynomial.
Using division algorithm, we get
x4−6x3−26x2+138x−35=(x2−4x+1)(x2−2x−35)
So, (x2−2x−35) is also a factor of the given polynomial.
x2−2x−35=x