Question

If two zeros of the polynomial x4-6x³-26x²+138x-35 are 2+_underoot 3 find zeros

Answer 1

Answer:

oots are -5 and 7

Step-by-step explanation:

given  2 zeros are 2±√3

sum of zeros=2+√3+2-√3=4

product of zeros =4-3=1

so the quadratic polynomial from given 2 zeros are x²-4x+1-----(1)

given x⁴-6x³-26x²+138x-35 ----(2)

dividing (2) by (1), we get x²-2x-35

→x²-7x+5x-35

→x(x-7)+5(x-7)

→(x+5)(x-7)

so the other roots are -5 and 7

Answer 2

${ \red{\mathfrak{\huge{A}}}}{\underline {\underline{\mathfrak{\huge{nswer}}}}}$


x(x-7)+5(x-7)
= (x+5)(x-7)

The roots are 5 and - 7