if two zeros of x^3+xa^2-5x-5 are √5 and-√5 then find its third zero
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Answer:x
3
+bx
2
+cx+d has zeros α,β and γ.
Then α+β+γ=−
a
b
Comparing x
3
+x
2
−5x−5
with ax
3
+bx
2
+cx+d
We have, a=1,b=1,c=−5 and d=−5
Now, x
3
+x
2
−5x−5 has two zeros
5
and −
5
So, α=
5
,β=−
5
,γ=?
∴α+β+γ=−
a
b
∴
5
+(−
5
)+γ=−1
∴γ=−1
Step-by-step explanation:
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