If two zeros of x^4+2x^3-5x^2+6x are 0 &1 then find the remaining zero s
Answers
Answered by
0
sum of zeroes = 0+1 + a + b = -2
a+ b= -3
now sum by taking 3 roots at a time
ab = -5
SO a= -5/b
-5 + b.b = -3b
b.b + 3b -5 =0
b= -3+- √9+20)/2
= -3+-√29)/2
a+ b= -3
now sum by taking 3 roots at a time
ab = -5
SO a= -5/b
-5 + b.b = -3b
b.b + 3b -5 =0
b= -3+- √9+20)/2
= -3+-√29)/2
Similar questions