Question

If U = 10±0.05 and V=20±0.01, find the relative

Answer 1

Answer:

Explanation:

A⃗ =−2i^+3j^ and

B⃗ =3i^+2j^

Dot product of two vector is

A⃗ ⋅B⃗ =(−2i^+3j^)⋅(B⃗ =3i^+2j^)

A⃗ ⋅B⃗ =(−2)(3)+(3)(2)=0

The dot product of two vector is zero which implies that they are perpendicular to each other. This can be obtained as fallows

A⃗ ⋅B⃗ =0

ABcosθ=0

Where A and B are the magnitude of two vectors A⃗  and B⃗  and θ is the angle between them.

⇒cosθ=0

⇒θ=cos−1(0)

⇒θ=900

vector product is given by

A×B=∣∣∣∣∣i^−23j^32k^00∣∣∣∣∣

A×B=i^(0–0)−j^(0–0)+k^(−4–9)

A×B=−13k^

or you can do using the properties

i^×j^=j^×j^=k^×k^=0

i^×j^=k^,j^×k^=i^andk^×i^=j^(clockwise)

i^×k^=−j^,j^×i^=−k^andk^×j^=−i^(anticlockwise)

A⃗ ×B⃗ =(−2i^+3j^)×(3i^+2j^)  

⇒A×B=−4(i^×j^)+9(j^×i^)

∴A×B=−4k^+9(−k^)=−13k^