If U = {3, 4, 5, 6, 7, 8, 9, X = {3,4}, Y = {5,67
and Z = {7,8,9}, then Y'(XnZ)' is equal to
(a) XUY (b) YUZ (c) (X UZ)' (d) X'Y'
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Answer:
Solution :
A'=U−A={1,3,5,7,9}A′=U-A={1,3,5,7,9}
B'=U−B={1,4,6,8,9}B′=U-B={1,4,6,8,9}
(i) A∪B={2,4,6,8,,3,5,7}A∪B={2,4,6,8,,3,5,7}
(A∪B)'={1,9}(A∪B)′={1,9}
A'∩B'={1,9}A′∩B′={1,9}
(ii) (A∩B)'=U−{2}(A∩B)′=U-{2}
={1,3,4,5,6,7,8,9}={1,3,4,5,6,7,8,9}
A'∪B'={1,3,5,7,4,6,8,9}A′∪B′={1,3,5,7,4,6,8,9}
hence proved
Step-by-step explanation:
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Answer:
Bro I think B is answers ....
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