if u=4 ,
v=3 find value of log(u+v)(u^2-v^2)
Answers
Answered by
21
Step-by-step explanation:
log(u+v) (u2-v2)
log(3+4)(16-9)
log(7)(7)
log(7^2)
2log7
Answered by
0
Given : u = 4 and v = 3
To Find : log (u + v)/(u² - v²)
Solution:
log (u + v)/(u² - v²)
(u² - v²) = ( u + v) ( u - v)
Hence (u + v)/(u² - v²) = 1/( u - v)
log (u + v)/(u² - v²)
= log ( 1/(u - v)(
u = 4 and v = 3
= log ( 1/(4 - 3))
= log ( 1/1)
= log 1
= 0
if its log (u + v) (u² - v²)
= log ( 7)(7)
= log 7²
= 2 log 7
= 2 ( 0.8451)
= 1.6902
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