Math, asked by kkarumugam91, 6 months ago

if u=4 ,
v=3 find value of log(u+v)(u^2-v^2)

Answers

Answered by Anonymous
21

Step-by-step explanation:

log(u+v) (u2-v2)

log(3+4)(16-9)

log(7)(7)

log(7^2)

2log7

Answered by amitnrw
0

Given : u = 4  and v = 3

To Find : log (u + v)/(u² -  v²)

Solution:

log (u + v)/(u² -  v²)

(u² -  v²)   = ( u + v) ( u - v)

Hence  (u + v)/(u² -  v²) = 1/( u - v)

log (u + v)/(u² -  v²)

= log ( 1/(u - v)(

u = 4 and v = 3

= log ( 1/(4 - 3))

= log ( 1/1)

= log 1

= 0

if its log (u + v) (u² -  v²)

= log ( 7)(7)

= log 7²

= 2 log 7

= 2 ( 0.8451)

= 1.6902

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