If u=60m/s theta=37⁰
Then find equation of trajectory?
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Answer:
The formula of equation of Trajectory=
y = h + xtan(∆) - gx²/2V₀²cos²(∆)
according to the question,
angel ∆= 37°
velicity v = 60 m/S
here you don't mention the h,
so, let initial height h = 0
putting the value we get,
y = 0 + 0.75x - 4.903x² / 2296.15
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