Question

If. U={a,b,c,d,e,f,g,i}. A={a,e,i,f}. B={c,e,i,g}. Then profe (AUB)'=A'nB'.​

Answer 1

Answer:

AUB={a,c,e,f,g,i}

(AUB)'={b,d}

Now,

A'={b,c,d,g}

B'={a,b,d,f}

A'nB'={b,d}

Hence, proved

Answer 2

Answer:

We know that complement of set A is

A

′

=U−A

Given U={a,b,c,d,e,f,g,h}

(i) A={a,b,c}

A

′

={d,e,f,g,h}

(ii) B={d,e,f,g}

∴B

′

={a,b,c,h}

(iii) C={a,c,e,g}

∴C

′

={b,d,f,h}

(iv) D={f,g,h,a}

∴D

′

={b,c,d,e}