If u and v are the zeroes of the polynomial f(x)= x² + x + 1, then 1/u + 1/v =
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f (x) = x^2 + x + 1
Where, a = 1 , b = 1 , c =1
One zero = u
Second zero = v
Sum of zeroes ( u + v ) = - b/a= -1 / 1 = -1
Product of zeroes ( u× v) = c/a = 1 / 1 = 1
We have to find value of , 1 / u+ 1 / v
Taking LCM
= u + v / uv
Keeping the values now,
= -1 / 1
= -1
Thus, 1 / u+ 1 / v = -1
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