Question

If u answer all these 3 questions with solution ill mark u as brainliest for sure

Answer 1

Answer:

too tiny

Explanation:

Answer 2

8)  

tension = fore acting on the bodies

F= kqq/r² k= constant    q=charge     r=distance between them

f=kq²/4l² is the answer.

9)

force excerted by +4q on Q=force excerted  by +q charge on Q

k×(4q×Q)/x²=k(q×Q)/(r-x)²   xis the distance between +4q and Q

(4qQ)/x²=(qQ)/(r-x)²

by solving this we get x=2r/3 from+4q

ie: r/3 from q

10)

when they got touched equal charges neutralizes and remaining charges will distribute uniformly. so when they touch  final charge on both body=16-8=8 and when they return back to initial position  both body will have 4 unit charge

then initial force = k×8×16/r²

final force =k×4×4/r²  =F/3