Question

If u can please solve this ​

Answer 1

Answer:

it is yur answer........................

Answer 2

Answer:

(x-a) is a factor of the polynomial

Therefore : f(-a) =0

Substituting values :

$2( { -a})^{2} + 2(a)( - a) + 5( - a) + 10 = 0$

$2 {a}^{2} - 2 {a}^{2} - 5a + 10 = 0$

$- 5a + 10 = 0$

Therefore :

$a = 2$