Math, asked by soudarpallymanaswini, 2 months ago

if u do it correct i will mark as brain list or report ​

Attachments:

Answers

Answered by riddhirajbhattacharj
1

Answer:

  Only zero and -1 can satisfy this equation.

∴ The Number of real values of x satisfying  [x^2] + 2[x] = x  is 2.

Step-by-step explanation:

[x^2] + 2[x] = x

⇒ x^2 = x - 2x

⇒ x^2 = -x

This means that for a number to satisfy this equation, its square needs to be equal to its negative value.

-1^2 = 1

∵ This only possible with -1,

∴ According to this only -1 can satisfy this formula.

However, if both sides have a value of zero then both sides will be equated, which means the equation will be satisfied.

∵ Any number to the power 0, any number multiplied by zero, zero added to itself, and the value of zero itself are all equal to zero,

∴ When x is substituted with zero, both sides become equal to zero.

[0^2] + 2[0] = 0

0 + 0 - 0 = 0

0  + 0 = 0

∴ Zero satisfies this equation.

∴ Only zero and -1 can satisfy this equation.

∴ The Number of real values of x satisfying  [x^2] + 2[x] = x  is 2.

Similar questions