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Step-by-step explanation:
In Δ BEC & Δ CFB
i. ∠BEC = ∠CFB = 90° [ Both are altitude, given ]
ii. BC = BC [ Common side ]
iii. BE = CF [ Given ]
∴ Δ BEC ≅ Δ CFB [RHS congruency ]
So, yes they are isosceles triangles.
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Answered by
3
Answer:
Triangle BEC and Triangle CFB are isosceles because:-
BC = BC ( as same base)
BE=CF ( as given)
As only both sides are equal it is isosceles...
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