if u have guts answer this....sum of a two digit number is 9 .when we interchange the digits , it is found that the resulting new number is greater than the original number by 27 .what is the two digit number
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Let tens number be x and ones place be y.
x+y=9 →1
Orginal number=10x+y
New number=10y+x
10x+y+27=10y+x
10x-x+y-10y+27=0
[9x-9y+27=0]/9
x-y+3=0
x-y=-3 →2
By eliminating →1 and →2.
x+y=9
x-y=-3
2x =6
x=3 →3
Substituting Eqn→3 in →1.
x+y=9
3+y=9
y=9-3
y=6
Therefore one number is 3 and other in 6.
So original number = 10x+y
=10X3+6
=30+6
=36
x+y=9 →1
Orginal number=10x+y
New number=10y+x
10x+y+27=10y+x
10x-x+y-10y+27=0
[9x-9y+27=0]/9
x-y+3=0
x-y=-3 →2
By eliminating →1 and →2.
x+y=9
x-y=-3
2x =6
x=3 →3
Substituting Eqn→3 in →1.
x+y=9
3+y=9
y=9-3
y=6
Therefore one number is 3 and other in 6.
So original number = 10x+y
=10X3+6
=30+6
=36
dakshdeep:
cool mam
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