If u =log tan (pi/4 +teta/2) then value of is
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sec θ
Step-by-step explanation:
Given
If y = log tan (pi/4 + θ/2) then value of dy/ dθ is
ANSWER
We have
y = log tan(π / 4 + θ/2)
dy / d θ = 1/tan(π/4 + θ/2) d/d θ [tan(π/4 + θ/2)] (log x’ = 1/x)
= cos (π/4 + π/2) / sin (π/4 + π/2) x sec^2(π/4 + θ/2) x d/dx (π/4 + θ/2) (since tan θ’= sec^2 θ )
= cos(π/4 + θ/2) / sin(π/4 + θ/2) x 1 / cos^2 (π/4 + θ/2) x 1/2
= 1 / 2 sin (π/4 + θ/2) Cos (π/4 + θ/2)
= 1 / sin (π/2 + θ) (since sin 2 θ = 2 sin θ cos θ)
= 1/cos θ
= sec θ
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