Question

If u = lx + my , v= mx - ly then show that ( partial u / partial x )( partial x / partial u )= l^ 2 / l^ 2 +m^ 2 (ii) ( partial u / partial y ) ( partial y / partial u )= l^ 2 +m^ 2 / l^ 2​

Answer 1

Answer:

Trigonometry, the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc).

Answer 2

Answer:

It is a proof question which had been proved as follows.

Step-by-step explanation:

We need to prove this result we assume our vector,

Say we have a function

f:Rn→Rf(v)=u⊤(v)

where u∈Rn

.

Taking the partial derivate of f

concerningo v

yields u

:

∂f/∂v=u

Why is that? This makes no sense to me. As f

returns real numbers, the rate of change in f

should be a real number, I would have assumed. Why is the rate of change a vector? Vectors are not even partof the  co-domain of f

.

Also, what subject do I need to look into for this? I just got confronted with that isolated claim that ∂f/∂v=u

,

$u=l i +mj\\v =mi-lj\\\frac{du}{dx} = l^{2} \\\frac{dv}{dx} =\frac{1}{m^{2} +l^{2} } \\\\= \frac{l^{2} }{l^{2} m^{2} }$

It gets prove in the following manner.

#SPJ3

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