If u = {set of natural numbers less than 20), A = factors of 18), and B = {odd numbers less than 15), then find (ii) A' U B' (1) (A n B)'
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Which is the sum of odd numbers beginning with 1?
The total of any set of sequential odd numbers beginning with 1 is always equal to the square of the number of digits, added together. If 1,3,5,7,9,11,…, (2n-1) are the odd numbers, then; Sum of first odd number = 1. Sum of first two odd numbers = 1 + 3 = 4 (4 = 2 x 2). Sum of first three odd numbers = 1 + 3 + 5 = 9 (9 = 3 x 3).
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Given, universal set, U={1,2,3,4,5,6,7}
A={1,2,5,7}
B={3,4,5,6}
(A∪B) ′
=U−(A∪B)
={1,2,3,4,5,6,7}−{1,2,3,4,5,6,7}
=ϕA ′ ∩B ′
=(U−A)n(U−B)
={3,4,6}n{1,2,7}
=ϕ
Hence (A∪B) ′
=A ′ ∩B ′
.
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