If u=sin-1(x³+y³/x+y) prove that dx/dy=2tanu
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Good Morning!!
This question can be solved by using "EULER'S THEOREM".
EULER'S THEOREM :- If a function say F(x,y) is homogeneous of n degree then ACCORDING TO EULER'S THEOREM.
x dF(x,y )/dx + y dF(x,y)/dy = n F (x,y)
GIVEN FUNCTION IS
U = Sin-¹ { (x³ + y³)/ (x + y) }
Sin u = { (x³ + y³) / (x + y) }
F(x,y) = Sin u = { (x³ + y³) / (x + y) }
BEFORE APPLYING EULER'S THEOREMFIRST WE, FIRST CHECK WETHER THIS FUNCTION IS HOMOGENEOUS OR NOT.
F(kx,ky) = Sin u = { (kx)³ + (ky)³ / (kx + ky)}
F(kx,ky) = Sin u = k² { (x³ + y³) / (x + y) }
F(kx,ky) = Sin u = k² F (x,y)
So, Given function. is homogeneous of degree two.
BY USING EULER'S THEOREM WE HAVE
x d (Sin u)/dx + y d ( Sin u )/dy = 2 Sin u
x Cos u du/dx + y Cos u du/dy = 2 Sin u
x du/dx + y du/dy = 2 Tan u
HENCE PROVED.
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