Question

If u=sin^-1(y/x) then du/dX=​

Answer 1

Answer:

$\frac{1}{ \sqrt{1 - (\frac{x}{y}) {}^{2} } }$

Step-by-step explanation:

given :- u = sin⁻¹(y/x)

find :- du/dx

As , we know that

★ d (sin⁻¹x)/dx = 1/√1-x² ( Diff basic Formula)

• ∴ similarly , in this case
• d[sin⁻¹(x\/y)]dx

$= \frac{1}{ \sqrt{1 - ( \frac{x}{y}) {}^{2} } } \: answer \:$

Answer 2

Answer:

here's your answer

hope it will help you