Question

if u.sinθ is 0 why u^2sin^2θ=maximum height

Answer 1

Answer:

If u.sin(theta) = 0

Then angle of projection

/

$theta \: = \: 0 {degree}$

So by the formula of finding maximum height

hmax = u^2 sin^2 theta / 2g

Here theta is 0 degree.

So h max = u^2 sin^2(0) / 2g

h max = 0

So the maximum height attained by the projectile is 0m.

Answer 2

Answer: The answer is in attachment.

Explanation: Check on attachment.