Question

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Answer 1

$1)x {}^{3} + {x}^{2} = 252$

$\: \: {x}^{5} = 252$

$x \times x \times x \times x \times x = 252$

$5x = 252$

$x = \frac{252}{5}$

$2)2 {x}^{3} + 5 {x}^{2} = 2500$

$7 {x}^{5} = 2500$

${x}^{5} = \frac{2500}{7}$

$3) {x}^{3} + 2 {x}^{2} = 288$

$2x {}^{5} = 288$

${x}^{5} = \frac{288}{2}$

${x}^{5} = 144$

$4)7 {x}^{3} + 6 {x}^{2} = 1728$

$13 {x}^{5} = 1728$

${x}^{5} = \frac{1728}{13}$

$5)3 {x}^{3} + x {}^{2} = 90$

$3 {x}^{5} = 90$

${x}^{5} = \frac{90}{3}$

${x}^{5} = 30$

$6)4 {x}^{3} + 7 {x}^{2} = 675$

$11x {}^{5} = 675$

$x {}^{5} = \frac{675}{11}$

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Answer 2

Answer:

1)x {}^{3} + {x}^{2} = 2521)x

3

+x

2

=252

\: \: {x}^{5} = 252x

5

=252

x \times x \times x \times x \times x = 252x×x×x×x×x=252

5x = 2525x=252

x = \frac{252}{5}x=

5

252

2)2 {x}^{3} + 5 {x}^{2} = 25002)2x

3

+5x

2

=2500

7 {x}^{5} = 25007x

5

=2500

{x}^{5} = \frac{2500}{7}x

5

=

7

2500

3) {x}^{3} + 2 {x}^{2} = 2883)x

3

+2x

2

=288

2x {}^{5} = 2882x

5

=288

{x}^{5} = \frac{288}{2}x

5

=

2

288

{x}^{5} = 144x

5

=144

4)7 {x}^{3} + 6 {x}^{2} = 17284)7x

3

+6x

2

=1728

13 {x}^{5} = 172813x

5

=1728

{x}^{5} = \frac{1728}{13}x

5

=

13

1728

5)3 {x}^{3} + x {}^{2} = 905)3x

3

+x

2

=90

3 {x}^{5} = 903x

5

=90

{x}^{5} = \frac{90}{3}x

5

=

3

90

{x}^{5} = 30x

5

=30

6)4 {x}^{3} + 7 {x}^{2} = 6756)4x

3

+7x

2

=675

11x {}^{5} = 67511x

5

=675

x {}^{5} = \frac{675}{11}x

5

=

11

675

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