Question

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Answer 1

Answer:

2A=2*(2X²-3Y-22+2X)=4X²-6Y-44+4X

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2B=2(22+2X+3X²+4Y.

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Step-by-step explanation:

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Answer 2

2A

2(2x2−3y−22+2x)

=(2)(2x2+−3y+−22+2x)

=(2)(2x2)+(2)(−3y)+(2)(−22)+(2)(2x)

=4x2−6y−44+4x

=4x2+4x−6y−44

2B

2(22+2x+3x2+4y)

=(2)(22+2x+3x2+4y)

=(2)(22)+(2)(2x)+(2)(3x2)+(2)(4y)

=44+4x+6x2+8y

=6x2+4x+8y+44

2C

2(10x+4y+2x2−11)

=(2)(10x+4y+2x2+−11)

=(2)(10x)+(2)(4y)+(2)(2x2)+(2)(−11)

=20x+8y+4x2−22

=4x2+20x+8y−22

(2A+2B)-2C

6x2−12x−6y+22

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