Question

if u=x^3+y^3+3xy, find 2u/2x ,2u/2y​

Answer 1

Step-by-step explanation:

$u = {x}^{3} + 3xy + {y}^{3}$

$\frac{du}{dx} = 3 {x}^{2} + 3y + {y}^{3} \\ \frac{dv}{dx} = {x}^{3} + 3x + 3 {y}^{2}$