If U={x|x€N, x<10) and A={x\x€N, 2<_x
<6) then (A')'is
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Step-by-step explanation:
U={x|x€N, x<10) and A={x\x€N, 2<_x
<6)
U= { 1,2,3,4,5,6,7,8,9) as x<10
A={x\x€N, 2≥ x}
so x={1,2}
A'= (3,4,5,6,7,8,9)
Now (A')' ={1,2} =A
Thus (A')'=A
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