If U ={x | x ∈ N, x < 10} and A = {x | x ∈ N, 2 ≤ x < 6} then (A′)′ is
Answers
Answer:
.
Step-by-step explanation:
Given sets are:-
U ={x | x ∈ N, x < 10}
=>U={1,2,3,4,5,6,7,8,9}
and A = {x | x ∈ N, 2 ≤ x < 6}
=>A={2,3,4,5,6}
Now, A'=U-A
=>A'={1,2,3,4,5,6,7,8,9} - {2,3,4,5,6}
=>A'= {1,7,8,9}
and (A')'= U- A'
=>(A')'=>{1,2,3,4,5,6,7,8,9} - {1,7,8,9}
=>(A')'= {2,3,4,5,6}
=>A
Therefore, (A')'=A
Concept:
A set is a collection of well defined elements or objects. A set is denoted by a capital letter, and the cardinal number of a set is enclosed in a curly bracket to indicate how many members there are in a finite set. Set A, for instance, is a collection of all the natural numbers, with the form A = 1, 2, 3, 5, 6, 7, 8, etc.
Given:
If U ={x | x ∈ N, x < 10} and A = {x | x ∈ N, 2 ≤ x < 6}
Find:
then (A′)′ is
Solution:
Given sets are:-
U ={x | x ∈ N, x < 10}
=>U={1,2,3,4,5,6,7,8,9}
and A = {x | x ∈ N, 2 ≤ x < 6}
=>A={2,3,4,5,6}
Now, A'=U-A
=>A'={1,2,3,4,5,6,7,8,9} - {2,3,4,5,6}
=>A'= {1,7,8,9}
and (A')'= U- A'
=>(A')'=>{1,2,3,4,5,6,7,8,9} - {1,7,8,9}
=>(A')'= {2,3,4,5,6}
=>A
Therefore, (A')'=A
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