If u =(x,y) = x² + y²+6x+12
then the
minimum value of function at (-3,0)
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1
Answer:
If u =(x,y) = x² + y²+6x+12
then the
minimum value of function at (-3,0) answer is 3
Answered by
1
Answer:
value of the function at (-3, 0) is
(-3) ² + 0 + 6(-3) +12 = 3
u(-3, 0) = 3
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