If u=x2y, then relative error in u, when there is an error of 0.01 both in x, y at x=1=y, is
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Step-by-step explanation:
Given that: f=x ^2
Hence,
df/ dx =2x
Therefore: Δf= df/dx Δx=2xΔx
The relative error in f is:
Δf/f = 2xΔx/x^2
Δf/f = 2Δx/x
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